[InstCombine] reassociateShiftAmtsOfTwoSameDirectionShifts(): fix miscompile (PR44802)

As input, we have the following pattern:
  Sh0 (Sh1 X, Q), K
We want to rewrite that as:
  Sh x, (Q+K)  iff (Q+K) u< bitwidth(x)
While we know that originally (Q+K) would not overflow
(because  2 * (N-1) u<= iN -1), we may have looked past extensions of
shift amounts. so it may now overflow in smaller bitwidth.

To ensure that does not happen, we need to ensure that the total maximal
shift amount is still representable in that smaller bitwidth.
If the overflow would happen, (Q+K) u< bitwidth(x) check would be bogus.

https://bugs.llvm.org/show_bug.cgi?id=44802
(cherry picked from commit 781d077afb0ed9771c513d064c40170c1ccd21c9)

1 files changed, 22 insertions, 2 deletions

diff --git a/llvm/lib/Transforms/InstCombine/InstCombineShifts.cpp b/llvm/lib/Transforms/InstCombine/InstCombineShifts.cpp
index fbff5dd4a8c..739579e2d38 100644
--- a/llvm/lib/Transforms/InstCombine/InstCombineShifts.cpp
+++ b/llvm/lib/Transforms/InstCombine/InstCombineShifts.cpp
@@ -23,8 +23,11 @@ using namespace PatternMatch;
 // Given pattern:
 //   (x shiftopcode Q) shiftopcode K
 // we should rewrite it as
-//   x shiftopcode (Q+K)  iff (Q+K) u< bitwidth(x)
-// This is valid for any shift, but they must be identical.
+//   x shiftopcode (Q+K)  iff (Q+K) u< bitwidth(x) and
+//
+// This is valid for any shift, but they must be identical, and we must be
+// careful in case we have (zext(Q)+zext(K)) and look past extensions,
+// (Q+K) must not overflow or else (Q+K) u< bitwidth(x) is bogus.
 //
 // AnalyzeForSignBitExtraction indicates that we will only analyze whether this
 // pattern has any 2 right-shifts that sum to 1 less than original bit width.
@@ -58,6 +61,23 @@ Value *InstCombiner::reassociateShiftAmtsOfTwoSameDirectionShifts(
   if (ShAmt0->getType() != ShAmt1->getType())
     return nullptr;
 
+  // As input, we have the following pattern:
+  //   Sh0 (Sh1 X, Q), K
+  // We want to rewrite that as:
+  //   Sh x, (Q+K)  iff (Q+K) u< bitwidth(x)
+  // While we know that originally (Q+K) would not overflow
+  // (because  2 * (N-1) u<= iN -1), we have looked past extensions of
+  // shift amounts. so it may now overflow in smaller bitwidth.
+  // To ensure that does not happen, we need to ensure that the total maximal
+  // shift amount is still representable in that smaller bit width.
+  unsigned MaximalPossibleTotalShiftAmount =
+      (Sh0->getType()->getScalarSizeInBits() - 1) +
+      (Sh1->getType()->getScalarSizeInBits() - 1);
+  APInt MaximalRepresentableShiftAmount =
+      APInt::getAllOnesValue(ShAmt0->getType()->getScalarSizeInBits());
+  if (MaximalRepresentableShiftAmount.ult(MaximalPossibleTotalShiftAmount))
+    return nullptr;
+
   // We are only looking for signbit extraction if we have two right shifts.
   bool HadTwoRightShifts = match(Sh0, m_Shr(m_Value(), m_Value())) &&
                            match(Sh1, m_Shr(m_Value(), m_Value()));