diff options
Diffstat (limited to 'llvm/test/Transforms/SCCP/sccptest.ll')
| -rw-r--r-- | llvm/test/Transforms/SCCP/sccptest.ll | 44 |
1 files changed, 20 insertions, 24 deletions
diff --git a/llvm/test/Transforms/SCCP/sccptest.ll b/llvm/test/Transforms/SCCP/sccptest.ll index f0a8244ecfa..84ba2d43cde 100644 --- a/llvm/test/Transforms/SCCP/sccptest.ll +++ b/llvm/test/Transforms/SCCP/sccptest.ll @@ -1,35 +1,31 @@ ; This is the test case taken from appel's book that illustrates a hard case ; that SCCP gets right. BB3 should be completely eliminated. ; -; RUN: llvm-upgrade < %s | llvm-as | opt -sccp -constprop -dce -simplifycfg | \ +; RUN: llvm-as < %s | opt -sccp -constprop -dce -simplifycfg | \ ; RUN: llvm-dis | not grep BB3 -int %testfunction(int %i0, int %j0) { +define i32 @testfunction(i32 %i0, i32 %j0) { BB1: br label %BB2 -BB2: - %j2 = phi int [%j4, %BB7], [1, %BB1] - %k2 = phi int [%k4, %BB7], [0, %BB1] - %kcond = setlt int %k2, 100 - br bool %kcond, label %BB3, label %BB4 - -BB3: - %jcond = setlt int %j2, 20 - br bool %jcond, label %BB5, label %BB6 - -BB4: - ret int %j2 - -BB5: - %k3 = add int %k2, 1 +BB2: ; preds = %BB7, %BB1 + %j2 = phi i32 [ %j4, %BB7 ], [ 1, %BB1 ] ; <i32> [#uses=2] + %k2 = phi i32 [ %k4, %BB7 ], [ 0, %BB1 ] ; <i32> [#uses=4] + %kcond = icmp slt i32 %k2, 100 ; <i1> [#uses=1] + br i1 %kcond, label %BB3, label %BB4 +BB3: ; preds = %BB2 + %jcond = icmp slt i32 %j2, 20 ; <i1> [#uses=1] + br i1 %jcond, label %BB5, label %BB6 +BB4: ; preds = %BB2 + ret i32 %j2 +BB5: ; preds = %BB3 + %k3 = add i32 %k2, 1 ; <i32> [#uses=1] br label %BB7 - -BB6: - %k5 = add int %k2, 1 +BB6: ; preds = %BB3 + %k5 = add i32 %k2, 1 ; <i32> [#uses=1] br label %BB7 - -BB7: - %j4 = phi int [1, %BB5], [%k2, %BB6] - %k4 = phi int [%k3, %BB5], [%k5, %BB6] +BB7: ; preds = %BB6, %BB5 + %j4 = phi i32 [ 1, %BB5 ], [ %k2, %BB6 ] ; <i32> [#uses=1] + %k4 = phi i32 [ %k3, %BB5 ], [ %k5, %BB6 ] ; <i32> [#uses=1] br label %BB2 } + |
