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-rw-r--r--lldb/source/Expression/IRMemoryMap.cpp47
1 files changed, 31 insertions, 16 deletions
diff --git a/lldb/source/Expression/IRMemoryMap.cpp b/lldb/source/Expression/IRMemoryMap.cpp
index 7bc2ed034de..d4f7b707349 100644
--- a/lldb/source/Expression/IRMemoryMap.cpp
+++ b/lldb/source/Expression/IRMemoryMap.cpp
@@ -125,33 +125,48 @@ IRMemoryMap::FindAllocation (lldb::addr_t addr, size_t size)
}
bool
-IRMemoryMap::IntersectsAllocation (lldb::addr_t addr, size_t size)
+IRMemoryMap::IntersectsAllocation (lldb::addr_t addr, size_t size) const
{
if (addr == LLDB_INVALID_ADDRESS)
return false;
- AllocationMap::iterator iter = m_allocations.lower_bound (addr);
+ AllocationMap::const_iterator iter = m_allocations.lower_bound (addr);
- if (iter == m_allocations.end() ||
- iter->first > addr)
- {
- if (iter == m_allocations.begin())
- return false;
-
- iter--;
+ // Since we only know that the returned interval begins at a location greater than or
+ // equal to where the given interval begins, it's possible that the given interval
+ // intersects either the returned interval or the previous interval. Thus, we need to
+ // check both. Note that we only need to check these two intervals. Since all intervals
+ // are disjoint it is not possible that an adjacent interval does not intersect, but a
+ // non-adjacent interval does intersect.
+ if (iter != m_allocations.end()) {
+ if (IntersectsAllocation(addr, size, iter->second.m_process_start, iter->second.m_size))
+ return true;
}
-
- while (iter != m_allocations.end() && iter->second.m_process_alloc < addr + size)
- {
- if (iter->second.m_process_start + iter->second.m_size > addr)
+
+ if (iter != m_allocations.begin()) {
+ --iter;
+ if (IntersectsAllocation(addr, size, iter->second.m_process_start, iter->second.m_size))
return true;
-
- ++iter;
}
-
+
return false;
}
+bool
+IRMemoryMap::AllocationsIntersect(lldb::addr_t addr1, size_t size1, lldb::addr_t addr2, size_t size2) {
+ // Given two half open intervals [A, B) and [X, Y), the only 6 permutations that satisfy
+ // A<B and X<Y are the following:
+ // A B X Y
+ // A X B Y (intersects)
+ // A X Y B (intersects)
+ // X A B Y (intersects)
+ // X A Y B (intersects)
+ // X Y A B
+ // The first is B <= X, and the last is Y <= A.
+ // So the condition is !(B <= X || Y <= A)), or (X < B && A < Y)
+ return (addr2 < (addr1 + size1)) && (addr1 < (addr2 + size2));
+}
+
lldb::ByteOrder
IRMemoryMap::GetByteOrder()
{
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