diff options
| -rw-r--r-- | llvm/test/Transforms/LoopVectorize/AArch64/predication_costs.ll | 14 |
1 files changed, 5 insertions, 9 deletions
diff --git a/llvm/test/Transforms/LoopVectorize/AArch64/predication_costs.ll b/llvm/test/Transforms/LoopVectorize/AArch64/predication_costs.ll index 8307a962b13..6b3a5b63042 100644 --- a/llvm/test/Transforms/LoopVectorize/AArch64/predication_costs.ll +++ b/llvm/test/Transforms/LoopVectorize/AArch64/predication_costs.ll @@ -15,10 +15,8 @@ target triple = "aarch64--linux-gnu" ; instruction. If we assume the block probability is 50%, we compute the cost ; as: ; -; Cost for vector lane zero: -; (udiv(1) + 2 * extractelement(0) + insertelement(0)) / 2 = 0 -; Cost for vector lane one: -; (udiv(1) + 2 * extractelement(3) + insertelement(3)) / 2 = 5 +; Cost of udiv: +; (udiv(2) + extractelement(6) + insertelement(3)) / 2 = 5 ; ; CHECK: Found an estimated cost of 5 for VF 2 For instruction: %tmp4 = udiv i32 %tmp2, %tmp3 ; CHECK: Scalarizing and predicating: %tmp4 = udiv i32 %tmp2, %tmp3 @@ -58,10 +56,8 @@ for.end: ; instruction. If we assume the block probability is 50%, we compute the cost ; as: ; -; Cost for vector lane zero: -; (store(2) + 2 * extractelement(0)) / 2 = 1 -; Cost for vector lane one: -; (store(2) + 2 * extractelement(3)) / 2 = 4 +; Cost of store: +; (store(4) + extractelement(6)) / 2 = 5 ; ; CHECK: Found an estimated cost of 5 for VF 2 For instruction: store i32 %tmp2, i32* %tmp0, align 4 ; CHECK: Scalarizing and predicating: store i32 %tmp2, i32* %tmp0, align 4 @@ -74,10 +70,10 @@ for.body: %i = phi i64 [ 0, %entry ], [ %i.next, %for.inc ] %tmp0 = getelementptr inbounds i32, i32* %a, i64 %i %tmp1 = load i32, i32* %tmp0, align 4 + %tmp2 = add nsw i32 %tmp1, %x br i1 %c, label %if.then, label %for.inc if.then: - %tmp2 = add nsw i32 %tmp1, %x store i32 %tmp2, i32* %tmp0, align 4 br label %for.inc |
