[libFuzzer] remove fuzzer-jobs.test which is flaky and not very useful

llvm-svn: 297543

1 files changed, 0 insertions, 31 deletions

diff --git a/llvm/lib/Fuzzer/test/fuzzer-jobs.test b/llvm/lib/Fuzzer/test/fuzzer-jobs.test
deleted file mode 100644
index 035c3afdf69..00000000000
--- a/llvm/lib/Fuzzer/test/fuzzer-jobs.test
+++ /dev/null
@@ -1,31 +0,0 @@
-REQUIRES: posix
-
-RUN: rm -rf %tmp
-RUN: mkdir %tmp && cd %tmp
-# Create a shared corpus directory
-RUN: rm -rf FuzzerJobsTestCORPUS
-RUN: mkdir FuzzerJobsTestCORPUS
-RUN: rm -f fuzz-{0,1}.log
-# Start fuzzer and in parallel check that the output files
-# that should be created exist.
-RUN: LLVMFuzzer-EmptyTest -max_total_time=4 -jobs=2 -workers=2 FuzzerJobsTestCORPUS > %t-fuzzer-jobs-test.log 2>&1 & export FUZZER_PID=$!
-# Wait a short while to give time for the child processes
-# to start fuzzing
-RUN: sleep 2
-# If the instances are running in parallel they should have created their log
-# files by now.
-RUN: ls fuzz-0.log
-RUN: ls fuzz-1.log
-# Wait for libfuzzer to finish.
-# This probably isn't portable but we need a way to block until
-# the fuzzer is done otherwise we might remove the files while
-# they are being used.
-RUN: while kill -0 ${FUZZER_PID}; do : ; done
-RUN: rm -f fuzz-{0,1}.log
-RUN: rm -rf FuzzerJobsTestCORPUS
-RUN: FileCheck -input-file=%t-fuzzer-jobs-test.log %s
-RUN: rm %t-fuzzer-jobs-test.log
-RUN: cd ../
-
-CHECK-DAG: Job 0 exited with exit code 0
-CHECK-DAG: Job 1 exited with exit code 0