It looks like the changes to the SRem logic of SimplifyDemandedUseBits

(fix for PR6165) are needed here too.

llvm-svn: 94801

1 files changed, 17 insertions, 8 deletions

diff --git a/llvm/lib/Analysis/ValueTracking.cpp b/llvm/lib/Analysis/ValueTracking.cpp
index 91e5bc3876b..f9331e76d0d 100644
--- a/llvm/lib/Analysis/ValueTracking.cpp
+++ b/llvm/lib/Analysis/ValueTracking.cpp
@@ -421,20 +421,29 @@ void llvm::ComputeMaskedBits(Value *V, const APInt &Mask,
   }
   case Instruction::SRem:
     if (ConstantInt *Rem = dyn_cast<ConstantInt>(I->getOperand(1))) {
-      APInt RA = Rem->getValue();
-      if (RA.isPowerOf2() || (-RA).isPowerOf2()) {
-        APInt LowBits = RA.isStrictlyPositive() ? (RA - 1) : ~RA;
+      APInt RA = Rem->getValue().abs();
+      if (RA.isPowerOf2()) {
+        APInt LowBits = RA - 1;
         APInt Mask2 = LowBits | APInt::getSignBit(BitWidth);
         ComputeMaskedBits(I->getOperand(0), Mask2, KnownZero2, KnownOne2, TD, 
                           Depth+1);
 
-        // If the sign bit of the first operand is zero, the sign bit of
-        // the result is zero. If the first operand has no one bits below
-        // the second operand's single 1 bit, its sign will be zero.
+        // The low bits of the first operand are unchanged by the srem.
+        KnownZero = KnownZero2 & LowBits;
+        KnownOne = KnownOne2 & LowBits;
+
+        // If the first operand is non-negative or has all low bits zero, then
+        // the upper bits are all zero.
         if (KnownZero2[BitWidth-1] || ((KnownZero2 & LowBits) == LowBits))
-          KnownZero2 |= ~LowBits;
+          KnownZero |= ~LowBits;
 
-        KnownZero |= KnownZero2 & Mask;
+        // If the first operand is negative and not all low bits are zero, then
+        // the upper bits are all one.
+        if (KnownOne2[BitWidth-1] && ((KnownOne2 & LowBits) != 0))
+          KnownOne |= ~LowBits;
+
+        KnownZero &= Mask;
+        KnownOne &= Mask;
 
         assert((KnownZero & KnownOne) == 0 && "Bits known to be one AND zero?"); 
       }