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authorDevin Coughlin <dcoughlin@apple.com>2017-03-01 17:48:39 +0000
committerDevin Coughlin <dcoughlin@apple.com>2017-03-01 17:48:39 +0000
commitbfa8e28dbb980294dff83f13c4e78dbd76d32461 (patch)
tree456ab77256ba5d996512e429b26770630f1e3193 /lldb/packages/Python/lldbsuite/test/expression_command/call-function
parent8f23dd6d68b047f6d556808e7e3fc35db5f9bcca (diff)
downloadbcm5719-llvm-bfa8e28dbb980294dff83f13c4e78dbd76d32461.tar.gz
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[analyzer] pr32088: Don't destroy the temporary if its initializer causes return.
In the following code involving GNU statement-expression extension: struct S { ~S(); }; void foo() { const S &x = ({ return; S(); }); } function 'foo()' returns before reference x is initialized. We shouldn't call the destructor for the temporary object lifetime-extended by 'x' in this case, because the object never gets constructed in the first place. The real problem is probably in the CFG somewhere, so this is a quick-and-dirty hotfix rather than the perfect solution. A patch by Artem Dergachev! rdar://problem/30759076 Differential Revision: https://reviews.llvm.org/D30499 llvm-svn: 296646
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