Recognize __unaligned keyword after type specifier

The __unaligned keyword can appear after a struct definition:

  struct foo {...} __unaligned *x;

llvm-svn: 223412

2 files changed, 2 insertions, 0 deletions

diff --git a/clang/lib/Parse/ParseDeclCXX.cpp b/clang/lib/Parse/ParseDeclCXX.cpp
index 79ae878520b..85f6303970a 100644
--- a/clang/lib/Parse/ParseDeclCXX.cpp
+++ b/clang/lib/Parse/ParseDeclCXX.cpp
@@ -1095,6 +1095,7 @@ bool Parser::isValidAfterTypeSpecifier(bool CouldBeBitfield) {
   case tok::kw_volatile:        // struct foo {...} volatile  x;
   case tok::kw_restrict:        // struct foo {...} restrict  x;
   case tok::kw__Atomic:         // struct foo {...} _Atomic   x;
+  case tok::kw___unaligned:     // struct foo {...} __unaligned *x;
   // Function specifiers
   // Note, no 'explicit'. An explicit function must be either a conversion
   // operator or a constructor. Either way, it can't have a return type.
diff --git a/clang/test/SemaCXX/MicrosoftExtensions.cpp b/clang/test/SemaCXX/MicrosoftExtensions.cpp
index ec3dfce52c1..57d6f0d6bef 100644
--- a/clang/test/SemaCXX/MicrosoftExtensions.cpp
+++ b/clang/test/SemaCXX/MicrosoftExtensions.cpp
@@ -79,6 +79,7 @@ struct M {
 
 // __unaligned handling
 typedef char __unaligned *aligned_type;
+typedef struct UnalignedTag { int f; } __unaligned *aligned_type2;
 
 
 template<typename T> void h1(T (__stdcall M::* const )()) { }