Handle a difference in lambda return type deduction between C++11 and C++1y: if

no return type is specified, C++11 will deduce a cv-qualified return type in
some cases, but C++1y never will.

llvm-svn: 187275

1 files changed, 15 insertions, 1 deletions

diff --git a/clang/test/SemaCXX/lambda-expressions.cpp b/clang/test/SemaCXX/lambda-expressions.cpp
index 8736afe4b0b..e8e2eb612a0 100644
--- a/clang/test/SemaCXX/lambda-expressions.cpp
+++ b/clang/test/SemaCXX/lambda-expressions.cpp
@@ -1,4 +1,5 @@
-// RUN: %clang_cc1 -std=c++0x -Wno-unused-value -fsyntax-only -verify -fblocks %s
+// RUN: %clang_cc1 -std=c++11 -Wno-unused-value -fsyntax-only -verify -fblocks %s
+// RUN: %clang_cc1 -std=c++1y -Wno-unused-value -fsyntax-only -verify -fblocks %s
 
 namespace std { class type_info; };
 
@@ -251,3 +252,16 @@ namespace PR16708 {
     return 0;
   };
 }
+
+namespace TypeDeduction {
+  struct S {};
+  void f() {
+    const S s {};
+    S &&t = [&] { return s; } ();
+#if __cplusplus <= 201103L
+    // expected-error@-2 {{drops qualifiers}}
+#else
+    S &&u = [&] () -> auto { return s; } ();
+#endif
+  }
+}