Class template partial specializations can be declared anywhere that

its definition may be defined, including in a class.

Also, put in an assertion when trying to instantiate a class template
partial specialization of a member template, which is not yet
implemented.

llvm-svn: 83469

1 files changed, 9 insertions, 0 deletions

diff --git a/clang/lib/Sema/SemaTemplateInstantiateDecl.cpp b/clang/lib/Sema/SemaTemplateInstantiateDecl.cpp
index 53252ec3f70..fa303659412 100644
--- a/clang/lib/Sema/SemaTemplateInstantiateDecl.cpp
+++ b/clang/lib/Sema/SemaTemplateInstantiateDecl.cpp
@@ -57,6 +57,8 @@ namespace {
     ParmVarDecl *VisitParmVarDecl(ParmVarDecl *D);
     Decl *VisitOriginalParmVarDecl(OriginalParmVarDecl *D);
     Decl *VisitClassTemplateDecl(ClassTemplateDecl *D);
+    Decl *VisitClassTemplatePartialSpecializationDecl(
+                                    ClassTemplatePartialSpecializationDecl *D);
     Decl *VisitFunctionTemplateDecl(FunctionTemplateDecl *D);
     Decl *VisitTemplateTypeParmDecl(TemplateTypeParmDecl *D);
     Decl *VisitUnresolvedUsingDecl(UnresolvedUsingDecl *D);
@@ -401,6 +403,13 @@ Decl *TemplateDeclInstantiator::VisitClassTemplateDecl(ClassTemplateDecl *D) {
 }
 
 Decl *
+TemplateDeclInstantiator::VisitClassTemplatePartialSpecializationDecl(
+                                   ClassTemplatePartialSpecializationDecl *D) {
+  assert(false &&"Partial specializations of member templates are unsupported");
+  return 0;
+}
+
+Decl *
 TemplateDeclInstantiator::VisitFunctionTemplateDecl(FunctionTemplateDecl *D) {
   // FIXME: Dig out the out-of-line definition of this function template?