[Hexagon] Specify vector alignment in DataLayout string

The DataLayout can calculate alignment of vectors based on the alignment
of the element type and the number of elements. In fact, it is the product
of these two values. The problem is that for vectors of N x i1, this will
return the alignment of N bytes, since the alignment of i1 is 8 bits. The
vector types of vNi1 should be aligned to N bits instead. Provide explicit
alignment for HVX vectors to avoid such complications.

llvm-svn: 260680

1 files changed, 6 insertions, 3 deletions

diff --git a/clang/lib/Basic/Targets.cpp b/clang/lib/Basic/Targets.cpp
index 2651cfe4ef4..aea14306c77 100644
--- a/clang/lib/Basic/Targets.cpp
+++ b/clang/lib/Basic/Targets.cpp
@@ -5697,9 +5697,12 @@ class HexagonTargetInfo : public TargetInfo {
 public:
   HexagonTargetInfo(const llvm::Triple &Triple) : TargetInfo(Triple) {
     BigEndian = false;
-    DataLayoutString = "e-m:e-p:32:32:32-"
-                       "i64:64:64-i32:32:32-i16:16:16-i1:8:8-"
-                       "f64:64:64-f32:32:32-v64:64:64-v32:32:32-a:0-n16:32";
+    // Specify the vector alignment explicitly. For v512x1, the calculated
+    // alignment would be 512*alignment(i1), which is 512 bytes, instead of
+    // the required minimum of 64 bytes.
+    DataLayoutString = "e-m:e-p:32:32:32-a:0-n16:32-"
+        "i64:64:64-i32:32:32-i16:16:16-i1:8:8-f32:32:32-f64:64:64-"
+        "v32:32:32-v64:64:64-v512:512:512-v1024:1024:1024-v2048:2048:2048";
     SizeType    = UnsignedInt;
     PtrDiffType = SignedInt;
     IntPtrType  = SignedInt;