ext4: free allocations by parse_path()

parse_path() malloc()s the entries in the array it's passed. Those
allocations must be free()d by the caller, ext4fs_get_parent_inode_num().
Add code to do this.

For this to work, all the array entries must be dynamically allocated,
rather than a mix of dynamic and static allocations. Fix parse_path() not
to over-write arr[0] with a pointer to statically allocated data.

Signed-off-by: Stephen Warren <swarren@nvidia.com>
Acked-by: Lukasz Majewski <l.majewski@samsung.com>
Tested-by: Lukasz Majewski <l.majewski@samsung.com>

1 files changed, 6 insertions, 2 deletions

diff --git a/fs/ext4/ext4_common.c b/fs/ext4/ext4_common.c
index c77e22d477..9fdbfe6e2d 100644
--- a/fs/ext4/ext4_common.c
+++ b/fs/ext4/ext4_common.c
@@ -615,8 +615,7 @@ static int parse_path(char **arr, char *dirname)
 	arr[i] = zalloc(strlen("/") + 1);
 	if (!arr[i])
 		return -ENOMEM;
-
-	arr[i++] = "/";
+	memcpy(arr[i++], "/", strlen("/"));
 
 	/* add each path entry after root */
 	while (token != NULL) {
@@ -746,6 +745,11 @@ end:
 fail:
 	free(depth_dirname);
 	free(parse_dirname);
+	for (i = 0; i < depth; i++) {
+		if (!ptr[i])
+			break;
+		free(ptr[i]);
+	}
 	free(ptr);
 	free(parent_inode);
 	free(first_inode);