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authorMiao Xie <miaox@cn.fujitsu.com>2013-09-09 13:19:42 +0800
committerChris Mason <chris.mason@fusionio.com>2013-09-21 11:05:23 -0400
commita482039889b85c45fc9616e65d560db7a35d4f54 (patch)
tree58482aa49aa50c30cdd2e7b496f30dd1c11ac860 /arch/tile
parent13fd8da98f79317d26277360d510caa1edf9bab3 (diff)
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Btrfs: allocate the free space by the existed max extent size when ENOSPC
By the current code, if the requested size is very large, and all the extents in the free space cache are small, we will waste lots of the cpu time to cut the requested size in half and search the cache again and again until it gets down to the size the allocator can return. In fact, we can know the max extent size in the cache after the first search, so we needn't cut the size in half repeatedly, and just use the max extent size directly. This way can save lots of cpu time and make the performance grow up when there are only fragments in the free space cache. According to my test, if there are only 4KB free space extents in the fs, and the total size of those extents are 256MB, we can reduce the execute time of the following test from 5.4s to 1.4s. dd if=/dev/zero of=<testfile> bs=1MB count=1 oflag=sync Changelog v2 -> v3: - fix the problem that we skip the block group with the space which is less than we need. Changelog v1 -> v2: - address the problem that we return a wrong start position when searching the free space in a bitmap. Signed-off-by: Miao Xie <miaox@cn.fujitsu.com> Signed-off-by: Josef Bacik <jbacik@fusionio.com> Signed-off-by: Chris Mason <chris.mason@fusionio.com>
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