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| author | Yi Li <yi.li@analog.com> | 2007-12-21 21:12:21 +0800 |
|---|---|---|
| committer | Bryan Wu <bryan.wu@analog.com> | 2007-12-21 21:12:21 +0800 |
| commit | c50e19f49830fb651b4b702ad2c3abcdf110b576 (patch) | |
| tree | 5ebce02ba1dd8d394982d83b9561493f9b0542a3 /arch/blackfin | |
| parent | a5bb85dfffd38714d83cf7798886462d7314b90a (diff) | |
| download | blackbird-op-linux-c50e19f49830fb651b4b702ad2c3abcdf110b576.tar.gz blackbird-op-linux-c50e19f49830fb651b4b702ad2c3abcdf110b576.zip | |
[Blackfin] arch: fix bug - make memcpy return the dest addr.
The memcpy() function returns the src pointer instead of the dst pointer.
This patch fix this bug.
Signed-off-by: Yi Li <yi.li@analog.com>
Signed-off-by: Bryan Wu <bryan.wu@analog.com>
Diffstat (limited to 'arch/blackfin')
| -rw-r--r-- | arch/blackfin/lib/memcpy.S | 8 |
1 files changed, 2 insertions, 6 deletions
diff --git a/arch/blackfin/lib/memcpy.S b/arch/blackfin/lib/memcpy.S index 2e6336492b4b..e654a18a0754 100644 --- a/arch/blackfin/lib/memcpy.S +++ b/arch/blackfin/lib/memcpy.S @@ -70,8 +70,8 @@ ENTRY(_memcpy) /* Check for aligned data.*/ R3 = R1 | R0; - R0 = 0x3; - R3 = R3 & R0; + R1 = 0x3; + R3 = R3 & R1; CC = R3; /* low bits set on either address? */ IF CC JUMP .Lnot_aligned; @@ -83,7 +83,6 @@ ENTRY(_memcpy) /* less than eight bytes... */ P2 = R2; LSETUP(.Lthree_start, .Lthree_end) LC0=P2; - R0 = R1; /* setup src address for return */ .Lthree_start: R3 = B[P1++] (X); .Lthree_end: @@ -95,7 +94,6 @@ ENTRY(_memcpy) /* There's at least eight bytes to copy. */ P2 += -1; /* because we unroll one iteration */ LSETUP(.Lword_loops, .Lword_loope) LC0=P2; - R0 = R1; I1 = P1; R3 = [I1++]; #if ANOMALY_05000202 @@ -120,7 +118,6 @@ ENTRY(_memcpy) .Lnot_aligned: /* From here, we're copying byte-by-byte. */ LSETUP (.Lbyte_start, .Lbyte_end) LC0=P2; - R0 = R1; /* Save src address for return */ .Lbyte_start: R1 = B[P1++] (X); .Lbyte_end: @@ -135,7 +132,6 @@ ENTRY(_memcpy) * Don't bother to work out alignment for * the reverse case. */ - R0 = R1; /* save src for later. */ P0 = P0 + P2; P0 += -1; P1 = P1 + P2; |
