diff options
Diffstat (limited to 'llvm/lib/Transforms/InstCombine/InstructionCombining.cpp')
-rw-r--r-- | llvm/lib/Transforms/InstCombine/InstructionCombining.cpp | 76 |
1 files changed, 56 insertions, 20 deletions
diff --git a/llvm/lib/Transforms/InstCombine/InstructionCombining.cpp b/llvm/lib/Transforms/InstCombine/InstructionCombining.cpp index 90e23239915..c7766568fd9 100644 --- a/llvm/lib/Transforms/InstCombine/InstructionCombining.cpp +++ b/llvm/lib/Transforms/InstCombine/InstructionCombining.cpp @@ -636,17 +636,35 @@ Value *InstCombiner::SimplifyUsingDistributiveLaws(BinaryOperator &I) { Value *A = Op0->getOperand(0), *B = Op0->getOperand(1), *C = RHS; Instruction::BinaryOps InnerOpcode = Op0->getOpcode(); // op' + Value *L = SimplifyBinOp(TopLevelOpcode, A, C, SQ.getWithInstruction(&I)); + Value *R = SimplifyBinOp(TopLevelOpcode, B, C, SQ.getWithInstruction(&I)); + // Do "A op C" and "B op C" both simplify? - if (Value *L = - SimplifyBinOp(TopLevelOpcode, A, C, SQ.getWithInstruction(&I))) - if (Value *R = - SimplifyBinOp(TopLevelOpcode, B, C, SQ.getWithInstruction(&I))) { - // They do! Return "L op' R". - ++NumExpand; - C = Builder.CreateBinOp(InnerOpcode, L, R); - C->takeName(&I); - return C; - } + if (L && R) { + // They do! Return "L op' R". + ++NumExpand; + C = Builder.CreateBinOp(InnerOpcode, L, R); + C->takeName(&I); + return C; + } + + // Does "A op C" simplify to the identity value for the inner opcode? + if (L && L == ConstantExpr::getBinOpIdentity(InnerOpcode, L->getType())) { + // They do! Return "B op C". + ++NumExpand; + C = Builder.CreateBinOp(TopLevelOpcode, B, C); + C->takeName(&I); + return C; + } + + // Does "B op C" simplify to the identity value for the inner opcode? + if (R && R == ConstantExpr::getBinOpIdentity(InnerOpcode, R->getType())) { + // They do! Return "A op C". + ++NumExpand; + C = Builder.CreateBinOp(TopLevelOpcode, A, C); + C->takeName(&I); + return C; + } } if (Op1 && LeftDistributesOverRight(TopLevelOpcode, Op1->getOpcode())) { @@ -655,17 +673,35 @@ Value *InstCombiner::SimplifyUsingDistributiveLaws(BinaryOperator &I) { Value *A = LHS, *B = Op1->getOperand(0), *C = Op1->getOperand(1); Instruction::BinaryOps InnerOpcode = Op1->getOpcode(); // op' + Value *L = SimplifyBinOp(TopLevelOpcode, A, B, SQ.getWithInstruction(&I)); + Value *R = SimplifyBinOp(TopLevelOpcode, A, C, SQ.getWithInstruction(&I)); + // Do "A op B" and "A op C" both simplify? - if (Value *L = - SimplifyBinOp(TopLevelOpcode, A, B, SQ.getWithInstruction(&I))) - if (Value *R = - SimplifyBinOp(TopLevelOpcode, A, C, SQ.getWithInstruction(&I))) { - // They do! Return "L op' R". - ++NumExpand; - A = Builder.CreateBinOp(InnerOpcode, L, R); - A->takeName(&I); - return A; - } + if (L && R) { + // They do! Return "L op' R". + ++NumExpand; + A = Builder.CreateBinOp(InnerOpcode, L, R); + A->takeName(&I); + return A; + } + + // Does "A op B" simplify to the identity value for the inner opcode? + if (L && L == ConstantExpr::getBinOpIdentity(InnerOpcode, L->getType())) { + // They do! Return "A op C". + ++NumExpand; + A = Builder.CreateBinOp(TopLevelOpcode, A, C); + A->takeName(&I); + return A; + } + + // Does "A op C" simplify to the identity value for the inner opcode? + if (R && R == ConstantExpr::getBinOpIdentity(InnerOpcode, R->getType())) { + // They do! Return "A op B". + ++NumExpand; + A = Builder.CreateBinOp(TopLevelOpcode, A, B); + A->takeName(&I); + return A; + } } // (op (select (a, c, b)), (select (a, d, b))) -> (select (a, (op c, d), 0)) |